3. A sailor on a small sailboat encounter shifting winds. She sails 2.00 km East then \( 3.50 \mathrm{~km}, 30.0^{\circ} \) South of East and \( 4.50 \mathrm{~km}, 45.0^{\circ} \) North of East. Find the \( x \) component and y -component, magnitude, and direction (10 pts).
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For the first leg, she sails 2.00 km East. This means the x component is 2.00 km and the y component is 0 km. For the second leg, she sails 3.50 km at an angle of 30.0 degrees South of East. This means the x component is 3.50 km * cos(30.0) = 3.03 km and the y Show more…
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A sailor in a small sailboat encounters shifting winds. She sails $2.00 \mathrm{~km}$ east, next $3.50 \mathrm{~km}$ southeast, and then an additional distance in an unknown direction. Her final position is $5.80 \mathrm{~km}$ directly east of the starting point (Fig. $\mathbf{P 1 . 6 0}$ ). Find the magnitude and direction of the third leg of the journey. Draw the vector-addition diagram and show that it is in qualitative agreement with your numerical solution.
$\bullet$ A sailor in a small sailboat encounters shifting winds. She sails 2.00 $\mathrm{km}$ east, then 3.50 $\mathrm{km}$ southeast, and then an additional distance in an unknown direction. Her final position is 5.80 $\mathrm{km}$ directly east of her starting point. (See Figure $1.28 . )$ Find the magnitude and direction of the third leg of the journey. Draw the vector addition diagram, and show that it in qualitative agreement with your numerical solution.
A sailor in a small sailboat encounters shifting winds. She sails 2.00 $\mathrm{km}$ east, then 3.50 $\mathrm{km}$ southeast, and then an additional distance in an unknown direction. Her final position is 5.80 $\mathrm{km}$ directly east of the starting point (Fig. P1.72). Find the magnitude and direction of the third leg of the journey. Draw the vector addition diagram and show that it is in qualitative agreement with your numerical solution.
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