00:03
Solution of this question is for an infinity for an infinitely charged seat the electric field the electric field is given by e is equal to to sigma divide by two epsilon.
00:58
Here, sigma is the surface charge density and epsilon is the permittivity of the medium.
01:05
Now the diagram is, sigma is equal to two, sigma plus is equal to two nanoculum per meter square.
01:26
This is seat one, seat one, sigma is equal to minus 5 nanocouple meter square this is sheet 2 and this distance is 4 centimeter suppose the seat are kept in vacuum so sigma is equal to sigma not this is epsilon 0 is equal to 8 .85 10 raise to par minus 12 coulomb square per newton meter square.
02:20
So for part a, part a, seat 1 and seat 2, this is 1, this is 1, this is 1 second and 3rd region.
02:39
And this distance is given 4 cm.
02:45
So at any point in region 1, point in region 1.
03:03
Electric field, electric field due to seat 1 is equal to sigma 1 divided by 2 epsilon 0.
03:16
Electric field due to c2 is equal to e2 is equal to sigma 2 divide by 2 epsilon 0 sigma e1 has negative x direction and e2 has positive x direction so electric field in region 1 electric field in region 1 is is equal to sigma 1 divided by 2 epsilon 0 minus sigma 2 divide by 2 epsilon 0 this is plus so 1 divided by 2 epsilon 0 sigma 1 plus sigma 2 so now, substituting given values 1 divided by 2 epsilon 0, sigma 1 is given 2.
04:50
Sigma 2 is given minus 5 nanoculum 10.
04:56
0 .m...