00:01
Here we have to find out the absorbance.
00:06
So let's write down the givens first.
00:09
Here, association constant is given.
00:11
Association constant is given as, let's say, kt is given as 6 x 10 raised to the power minus 4.
00:23
Now, we can convert it into association constant.
00:31
So, it would be 1 divided by association constant.
00:37
1 divided by 6 x 10 raised to the power minus 4.
00:41
So it's 1600.
00:43
1600 is our association constant.
00:46
Now, molarity of solution a and b.
00:52
Molarity is given as 0 .01 molar.
00:58
Let's write down the reaction first.
00:59
So a plus here ab.
01:04
So, at initial point, a is 0 .01, b is 0 .01 and ab is 0 .005...