3. After the skier on the 37° hill in Problem 2 had been moving for 5.0 s, the friction of the snow suddenly increased and made the net force on the skier zero. What is the new coefficient of friction?
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Step 1: The force of friction becomes equal to the normal force acting on the body, which is equal to \( m \cdot g \cdot \cos(37^\circ) \). Show more…
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