Question

Rain Drop $\rho_{A,sat} = 958 \ kg/m^3$ Air-Water Mixture @ 300 K $\nu = 85 \times 10^{-6} m^2/s$ $k = 3 \times 10^{-3} W/m\cdot K$ $\rho_{A,mix} = 25 kg/m^3$ $Sc = 45$ $D_{A/B} = 2.3 \times 10^{-5} m^2/s$

          Rain Drop
$\rho_{A,sat} = 958 \ kg/m^3$
Air-Water Mixture @ 300 K
$\nu = 85 \times 10^{-6} m^2/s$
$k = 3 \times 10^{-3} W/m\cdot K$
$\rho_{A,mix} = 25 kg/m^3$
$Sc = 45$
$D_{A/B} = 2.3 \times 10^{-5} m^2/s$

Rain Drop
ρA,sat = 958 kg/m^3
Air-Water Mixture @ 300 K
ν = 85 × 10^-6 m^2/s
k = 3 × 10^-3 W/m· K
ρA,mix = 25 kg/m^3
Sc = 45
DA/B = 2.3 × 10^-5 m^2/s

Added by Patricia G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Thanks for your feedback!

As the rain in question two falls, there is also mass transfer from the liquid water to the air-water mixture surrounding each drop. a. Using the properties shown, what is the mass flux between a single drop and the surrounding air? b. How does your solution to part a relate to evaporative cooling, the changes of air temperature, and humidity during a rainstorm? Rain Drop Pa,sat = 958 kg/m^3 Air-Water Mixture @ 300 K = 8.51 Ã— 10^-6 m^2/s k = 3 Ã— 10^-3 W/m K PA,mix = 25 kg/m^3 Sc = 45 Da/B = 2.3 Ã— 10^-5 m^2/s