Question

3 Assembly Language Programming The final part of this assignment involves writing an assembly language program that reads an 8-bit value from the switch input and displays the value in hexadecimal format on the SSD units (and on the green LEDs). Start by working from the lights.s file. As in the tutorial, create .equ macros for the addresses of the PIO ports. Create one each for leds, switches, hexa, and hexb. These may have changed with the addition of the new PIO ports. To display a value on the seven-segment display, you need to issue a stbio instruction to the address from the Qsys layout. The value you write to the address is a 7-bit value which corresponds to each segment of the display. Recall that the SSD device uses negative-asserted true logic, so a 0 bit value activates an LED segment and a 1 bit value deactivates a segment. For example, if we wanted to make an 8 display, we would write 7 zeroes to the display: 0x00. To make only the top light segment display (segment 0), you would write all ones, except for the lowest bit (bit 0): 0xfe or 0x7e (the highest-order bit is ignored, since the SSD inputs are only seven-bit values). Lookup Table: Rather than using the hardware circuitry that we created in Lab 2, we want to use a software lookup table to display the correct value on the SSD. To implement this, we will use a label, lut:, to mark the beginning of some constant data in our assembly language program. To understand how a lookup table is implemented in assembly language, assume that we wanted to have a three-element array constant, a, with a[0]=5, a[1]=6, and a[2]=7. We would arrange this in our assembly language program like this: .data a: .word 5 .word 6 .word 7 .end This code is placed after the end of our assembly program, before the .end marker. The label a: marks the address of the first element of the array (index 0). Each element is stored in a four-byte word, so to compute a[2], we would use the base address stored in a, and add the size of each element (4 bytes) times the number of elements to skip over (2): a[2]=Mem[a+(42)] Construct a 16-element array, one for each possible 4-bit combination of values to display on an SSD. The value of each array element should be a 32-bit word, with the lowest 7-bits containing the bit pattern to illuminate the correct segments for the corresponding 4-bit hexadecimal value. For example, the value of lut[8] should contain the 7-bit pattern (0x00) to illuminate all segments on the display. Once you have completed your array, modify the main loop driver to write the 8-bit value from the switches to both HEXA and HEXB. You will have to read the 8-bit value into two registers, use these values to determine the offsets into the lookup table, load the pattern values from the LUT and write them each to the correct SSD, as well as the LEDs. As an example, let's say that the value read from the switches is 11110001 (i.e. 0xf1). You need to move 0001 into one register and 1111 into another. Next, load the value at lut + 41 into a new register and lut + 4*15 into another. These registers should now contain the 7-bit patterns that can be written to the SSD using the stbio instruction.

Name: 3 assembly language programming the final part of this assignment involves writing an assembly language program that reads an 8 bit value from the switch input and displays the value in hexa 28415
Uploaded: 2023-01-30T16:21:21-08:00
Duration: 1 min 38 s
Channel: Sri K
Description: 3 assembly language programming the final part of this assignment involves writing an assembly language program that reads an 8 bit value from the switch input and displays the value in hexa 28415

3 Assembly Language Programming
The final part of this assignment involves writing an assembly language program that reads an 8-bit value from the switch input and displays the value in hexadecimal format on the SSD units (and on the green LEDs). Start by working from the lights.s file. As in the tutorial, create .equ macros for the addresses of the PIO ports. Create one each for
leds, switches, hexa, and hexb. These may have changed with the addition of the new PIO ports.
To display a value on the seven-segment display, you need to issue a stbio instruction to the address from the Qsys layout. The value you write to the address is a 7-bit value which corresponds to each segment of the display. Recall that the SSD device uses negative-asserted true logic, so a 0 bit value activates an LED segment and a 1 bit value deactivates a segment. For example, if we wanted to make an 8 display, we would write 7 zeroes to the display: 0x00. To make only the top light segment display (segment 0), you would write all ones, except for the lowest bit (bit 0): 0xfe or 0x7e (the highest-order bit is ignored, since the SSD inputs are only seven-bit values).
Lookup Table: Rather than using the hardware circuitry that we created in Lab 2, we want to use a software lookup table to display the correct value on the SSD. To implement this, we will use a label, lut:, to mark the beginning of some constant data in our assembly language program.
To understand how a lookup table is implemented in assembly language, assume that we wanted to have a three-element array constant, a, with a[0]=5, a[1]=6, and a[2]=7. We would arrange this in our assembly language program like this:
.data
a:
.word 5
.word 6
.word 7
.end
This code is placed after the end of our assembly program, before the .end marker. The label a: marks the address of the first element of the array (index 0). Each element is stored in a four-byte word, so to compute a[2], we would use the base address stored in a, and add the size of each element (4 bytes) times the number of elements to skip over (2): a[2]=Mem[a+(4*2)]
Construct a 16-element array, one for each possible 4-bit combination of values to display on an SSD. The value of each array element should be a 32-bit word, with the lowest 7-bits containing the bit pattern to illuminate the correct segments for the corresponding 4-bit hexadecimal value. For example, the value of lut[8] should contain the 7-bit pattern (0x00) to illuminate all segments on the display.
Once you have completed your array, modify the main loop driver to write the 8-bit value from the switches to both HEXA and HEXB. You will have to read the 8-bit value into two registers, use these values to determine the offsets into the lookup table, load the pattern values from the LUT and write them each to the correct SSD, as well as the LEDs.
As an example, let's say that the value read from the switches is 11110001 (i.e. 0xf1). You need to move 0001 into one register and 1111 into another. Next, load the value at lut + 4*1 into a new register and lut + 4*15 into another. These registers should now contain the 7-bit patterns that can be written to the SSD using the stbio instruction.

Added by Guillermo O.

We constantly seem to be pricing ourselves out of some markets and not charging enough in others. Our pricing policy is pretty simple: we mark up our full manufacturing cost by 50%. That means a computer that costs us $2,000 to manufacture will sell for $3,000. Until now I thought this was a workable approach, but now I’m not so sure. Steve Works, CEO, Cortland Manufacturing, Inc. (CMI) Steve’s Controller, Sally Nomer, had just told him that she believed the computers might be priced inappropriately. Steve continued: When I was at Leland [School of Management] I focused most of my attention on operations and marketing, convinced that those were the keys to my successful career. Cost accounting was boring and not relevant. But now my accountant is telling me that I need to think about a new way to assign manufacturing overhead to products, and I don’t even know where to start! I never dreamed that some day my career would come to this. I wish I’d paid more attention to those classes so I could understand what is going on here. I’m lost. BACKGROUND CMI manufactures several different models of computers, distributed to retail outlets throughout the 50 states. The company is proud of the user-friendly computers it produces, in particular their graphics capability. CMI claims the superb graphics are what distinguish its products from competitors. CMI purchases raw materials in components and subassemblies made to its specifications from a very small group of highly reliable suppliers. It uses a single facility to house both manufacturing facility and administrative and sales offices. The factory workers operate three kinds of machines. Inspecting machines check the raw materials and test components and subassemblies to assure they are working to specifications. Soldering machines solder various components as necessary. Finally assembly machines put all the components and subassemblies together into finished computers. The processes can vary by computer model. Depreciation, maintenance and repairs on the three types of machines account for about 40% of CMI’s overhead cost. The remainder of the overhead is made up of labor involved in receiving and handling the raw materials, adjusting and setting up machines for each new batch of computers, and inspecting and packing finished computers for shipping. Additional costs include insurance and depreciation on handling equipment, supplies, and utilities. The actual manufacturing effort (soldering, inspecting and assembly) is primarily automated, so CMI uses very little direct labor. The company also operates on a lean production model, so almost no inventories exist at the end of any period. Most of the computers are sold in large orders to national electronic chains. However, the Cortland 2000 is not such a machine. It represents a recent effort by CMI to enter the scientific computing market. The quantity manufactured and sold of this machine is expected to be much lower than other models even when it gains its hoped-for market share. Fewer customers exist for this more sophisticated, powerful, high-priced machine. Nonetheless, Mr. Works has believed from the conception of this product that, when all manufacturing costs were considered, the Cortland 2000 would contribute a reasonable amount to CMI’s selling and administrative costs and profit. The name recognition it brought in its elite community should enhance sales of the more generally used computers. FINANCIAL INFORMATION CMI budgeted direct labor costs for 2010 at $60,000,000. Based on expected sales, the company estimated that raw material purchased and used would be $300,000,000. Manufacturing overhead was budgeted at $196,000,000. It is currently allocated to production on the basis of machine hours (MH). As mentioned above, computers are priced at full production cost plus a mark-up of 50%. EXHIBIT 1 shows the expected direct manufacturing costs for two of the company’s computers. The Cortland 1000 is a very popular computer with a large production and sales volume. By contrast, the Cortland 2000, described above, is a state-of-the-art scientific computer with several special features. In particular, the Cortland 2000 a. Uses a new processing chip imported from Sweden. b. Has special patented random access memory (RAM) that gives it extremely high input/output speed. c. Is manufactured in very small batches to assure uniform quality from one computer to the next, to satisfy the users of the machines who have very high expectations for the performance of the machines they purchase. Mr. Works’ concerns arose when Ms. Nomer told him that she thought the company’s traditional overhead allocation system was providing misleading cost information about the different types of products. She developed an analysis of the 2010 manufacturing overhead costs, shown in EXHIBIT 2. She classified the overhead costs described above into activities. She also gathered data, shown in EXHIBIT 3, for the 2010 production of the Cortland 1000 and the Cortland 2000. Mr. Works commented on the data: I don’t know quite what to make of all this. Clearly I need some further explanation and analysis. I guess what I really need is some sense of what is the true manufacturing cost of each computer. I thought I knew that, but I didn’t really. Even though we cannot at this point change prices for 2010, we at least need to know if we’re covering full production cost on the Cortland 2000 and have something left to contribute to the company’s selling, general and administrative expenses. I thought this was so, but now … well, I’m not so sure. We’d better figure this out before we begin our budget cycle for 2011. Maybe I need to go back to school! EXHIBIT 1 Direct Manufacturing Costs for ONE Computer Cortland 1000 Cortland 2000 Direct Material $1,000 $2,500 Direct Labor $200 $400 EXHIBIT 2 Analysis of 2010 Budgeted Manufacturing Overhead Costs Activity Cost driver Budgeted activity (for entire company) Budgeted cost Receive/handle raw material Orders received 200 orders $90,000,000 Adjust/set up machines Number of setups 2,000 setups $12,000,000 Inspect, pack, ship computers Batches 500 batches $60,000,000 Inspect raw materials Inspection hours 200,000 insp. hr. $10,000,000 Solder parts Soldering hours 200,000 sdr. hr. $12,000,000 Assemble computers Assembly hours 100,000 assm. hr. $12,000,000 Total overhead $196,000,000 EXHIBIT 3 Production Data for Cortland 1000 and Cortland 2,000 Computers Item Measure Cortland 1000 Cortland 2000 Budgeted production Number of computers 20,000 5,000 Received order size* Size of order 10,000 500 Batch size Number of computers 5,000 100 Machine setups Number of s/u per batch 5 6 Inspecting time (Raw mat.) Hours / computer 1 2 Soldering time Hours / computer 3 1 Assembly time Hours / computer 1 1 * “Received order size” is the number of computers one order of raw materials will build. Thus, for example, (see above) the company receives 2 orders of raw materials for the Cortland 1,000. Calculation: 20,000 computers per year, divided by 10,000 computers each order will build = 2 orders per year. REQUIRED: Don’t try to begin answering questions until you have studied the case information carefully. Careless reading will result in careless errors! Just take a few extra minutes to understand it all. 1. Calculate the predetermined overhead rate the company is currently using. (Where should you look for the machine hours?) 2. Using the information from the exhibits and Q1, calculate the manufacturing cost of ONE Cortland 1000 and ONE Cortland 2000. 3. Calculate the selling price, under the current system, of ONE Cortland 1000 and ONE Cortland 2000. 4. Next, you are going to begin to analyze the ABC system. In order to do this, however, your study of Exhibits 2 and 3 should have told you that you are going to have to convert the information the company currently measures into the information you need for the ABC analysis. First, how many raw material orders did the company receive for each model? 5. How many batches of each model did the company pack and ship? 6. How many machine setups does Cortland do for each model? 7. Calculate a rate for each activity in Exhibit 2. 8. Use the rates calculated in Q7 to apply overhead to each product line: Cortland 1000 and 2000. 9. Calculate the overhead per computer for a Cortland 1000 and a Cortland 2000. 10. Calculate the manufacturing cost of ONE Cortland 1000 and ONE Cortland 2000 using ABC overhead allocation. 11. Show how the company would determine a selling price for each model under the ABC system. 12. Should Mr. Works adopt an ABC system for internal analysis? Your answer should address the question very specifically to this case – no generalities about ABC from the book. It should contain two points in favor of ABC, and two drawbacks that he should be aware of. 13. Mr. Works is also concerned about future product development. They have several new models under development at this time. If an ABC system is used, list two characteristics of a new model that will make it more costly to manufacture.

Sri K.

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