00:01
To calculate the ph and the poh of water at 298 kelvin or 25 degrees celsius, we recognize the water undergoes auto -protolysis, and in the process it produces hydroxide and hydronium ion.
00:19
Kw is then equal to the product of these two concentrations.
00:29
At 25 degrees celsius, kw is equal to 1 .0 times 10 to the negative 14.
00:38
Because the stoichiometry of this reaction is one to one, then if there are no other sources of hydroxide and hydronium, except through autoprotolysis, these two concentrations are equal to each other.
00:53
So we can then go back to our kw expression, and the hydronium concentration multiplied by the hydroxide concentration, which is the hydrogenium concentration.
01:06
So the hydrogenum concentration squared is equal to 1 .1.
01:10
Times 10 to the negative 14.
01:13
So that gives us a hydronium concentration, which is also equal to the hydroxide concentration of 1 .0 times 10 to the negative 7.
01:25
So we get a ph that is equal to the negative log of the hydronium concentration, that being 7.
01:36
And a p .o .h that is equal to the negative log of the hydroxide concentration, also gives us 7...