Calcium carbonate is decomposed by heating. The balanced equation for this reaction is CaCO3(s) → CaO(s) + CO2(g) + heat. What is the theoretical yield of CaO if 24.8 g CaCO3 is heated? How much is the % yield in the reaction if 12 grams of CaO is obtained?
Added by Patricia W.
Step 1
The molar mass of CaCO3 is: Ca: 40.08 g/mol C: 12.01 g/mol O: 16.00 g/mol Total molar mass = 40.08 + 12.01 + (3 * 16.00) = 100.09 g/mol Show more…
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