Calcium carbonate reacts with HCl according to the following reaction: CaCO3 + 2 HCl → H2 + CO2 + CaCl2. How many grams of CaCO3 are required to react with 14.3 g HCl? Molar masses: HCl 36.5 g/mol; CaCO3 100.09 g/mol.
Added by Taylor R.
Step 1
3 grams. Use the molar mass of HCl (36.5 g/mol) for this calculation. \[ \text{Moles of HCl} = \frac{\text{Mass of HCl}}{\text{Molar mass of HCl}} = \frac{14.3 \, \text{g}}{36.5 \, \text{g/mol}} \] Show more…
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