3. Determine the internal forces at pt C in the pipe system. The loadings are: $\vec{F_1} = \{-24\hat{i} - 10\hat{k}\} \text{ lb}$ $\vec{F_2} = \{-80\hat{i}\} \text{ lb}$ $\vec{M} = \{-30\hat{k}\} \text{ft} \cdot \text{lb}$
Added by Anne P.
Close
Step 1
We have a pipe system with a loading at point C. The loadings are given as follows: - F₁ = -242-10k - F₂ = 22 - E - 8003 - M = {-30k} ft·16 Show more…
Show all steps
Your feedback will help us improve your experience
Madhur L and 88 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Consider the pipe assembly in the Figure below: The applied forces are defined as F1 = (100i - 120j + 75k) kN and F2 = (-200i + 250j + 100k) kN. 1. Determine the resultant force vector F in kN. 2. Determine the position vector rA in m. 3. Determine the moment of the forces M0 about point O in kNm. Express all the results in vectorial form referring to the coordinate system given in the figure. Note that the X-, Y-, Z-axis positive direction is towards the respective letters.
Madhur L.
Determine the $x, y, z$ components of force and moment at point $C$ in the pipe assembly. Neglect the weight of the pipe. The load acting at $(0,3.5 \mathrm{ft}, 3 \mathrm{ft})$ is $\mathbf{F}_{1}=\{-24 \mathbf{i}-10 \mathbf{k}\} 1 \mathbf{b}$ and $\mathbf{M}=\{-30 \mathbf{k}\} \mathrm{lb} \cdot \mathrm{ft} \quad$ and $\quad \mathrm{at}$ point $(0,3.5 \mathrm{ft}, 0) \mathbf{F}_{2}=\{-80 \mathrm{i}\} \mathrm{lb}$.
Express each force acting on the pipe assembly in Cartesian vector form, then specify the magnitude of F3 and its coordinate direction angles α, β, and γ so that the resultant force FR = {9j} kN
Supreeta N.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD