00:01
So here in this question we are given the circuit from here the signal rs is entering which is further moving towards the gc then after gc it is moving towards the gs then from here we are given out the cs signal where h is connected in this point from here.
00:19
So h is connected which is further connected to this signal.
00:22
So for the control system which we are given here we have to find out the open loop transfer function from here the closed loop transfer function and the characteristic equations are given.
00:33
So firstly we are considering about the open loop transfer function.
00:39
So open loop transfer function from here is given as oltf that is equals to g of c multiplied by the g of s multiplied by the h of s where we are given the value of g of c of s that is equals to one divided by s plus two we are given the value of g of s of s that is equals to 10 divided by the s plus three.
01:05
10 divided by s plus three multiplied by the s plus one and we are given the value of h that is equals to one.
01:13
So from here this is a case which we are given here so the value of gc is equals to one divided by the s plus two that is multiplied by the 10 that is divided by the s plus three multiplied by the s plus 1 multiplied by the 1.
01:28
So this from here is equals to 10 that is divided by the s plus 2 s plus 3 s plus 1 so this from here become equals to 10 that is divided by the s raised to the power three plus six of x raised to the power two plus 11 of s plus six.
01:45
So this is the value of that is open loop transfer function hence the answer to the part a...