3. Find k such that the following points are collinear: A(1,k) B(k-1,4) C(1,3). 4. Find the line(s) containing the point (-1,4) and lying at a distance of 5 from the point (6,3). 5. Given the points P(1,10) and Q(-7,6). Find the line that is orthogonal to the line e: 4x-3y=14 and that bisects the line segment [PQ]. 6. Find the points on the line x+7y-52=0 that lie at a distance of 5 from the point (6,3). 7. Find the equation of the line containing the point (-2,-4) for which the algebraic sum of the segments cut off on the two coordinate axes is 3.
Added by Patricia C.
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To do this, we can use the slope formula: Slope of AB = (y2 - y1) / (x2 - x1) Slope of BC = (y3 - y2) / (x3 - x2) If the points are collinear, the slopes of AB and BC will be equal. So, we have: (k - 4) / (L - (k - 1)) = (3 - 4) / (1 - (k - 1)) Solving for k, Show more…
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