Question

3. Find the inverse Laplace transform $x(t)$ of the function $X(s)$ given below. $X(s) = \frac{s^6 + 4s^5 + 9s^4 + 12s^3 + 12s^2 + 9s + 5}{(s^2 + 2s + 1)^2}$

          3. Find the inverse Laplace transform $x(t)$ of the function $X(s)$ given below.
$X(s) = \frac{s^6 + 4s^5 + 9s^4 + 12s^3 + 12s^2 + 9s + 5}{(s^2 + 2s + 1)^2}$

3. Find the inverse Laplace transform x(t) of the function X(s) given below.
X(s) = (s^6 + 4s^5 + 9s^4 + 12s^3 + 12s^2 + 9s + 5)/((s^2 + 2s + 1)^2)

Added by John R.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Tony Hartman

05/08/2022

Step 1

Step 1: We can rewrite the numerator as follows: $s^6 + 4s^5 + 9s^4 + 12s^3 + 12s^2 + 9s + 5 = (s^2 + 2s + 1)^3$ Show more…

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3. Find the inverse Laplace transform $x(t)$ of the function $X(s)$ given below. $X(s) = \frac{s^6 + 4s^5 + 9s^4 + 12s^3 + 12s^2 + 9s + 5}{(s^2 + 2s + 1)^2}$