Question

7. [-/2 Points] DETAILS OSPRECALC1 10.3.155-160.WA.TUT. A parabola is given by the following equation. Identify the location of the vertex and the focus. $(y+4)^2 = 20(x-2)$ vertex $(x, y) = (…, …)$ focus $(x, y) = (…, …)$

          7. [-/2 Points] DETAILS
OSPRECALC1 10.3.155-160.WA.TUT.
A parabola is given by the following equation. Identify the location of the vertex and the focus.
$(y+4)^2 = 20(x-2)$
vertex $(x, y) = (…, …)$
focus $(x, y) = (…, …)$

Added by Michelle C.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Khushbu Rani

Step 1

The equation of a parabola with a focus at (a,b) and a directrix at y = c is given by: (x-a)^2 = 4c(y-b) Show more…

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