00:01
Hello students, in this question for the first part of the question we have to calculate the equivalent capacitance of the circuit.
00:08
Given that three capacitors are there in this, these two capacitors are connected in series and this one is connected in parallel with the other two.
00:18
So first let's take the capacitors that are connected in series.
00:22
Here before that let it name the capacitors.
00:25
This is c1, this is c2 and this is c3.
00:29
Here c2 and c3 are in series.
00:36
So for the capacitors in series we know the formula that is equivalent capacitance that is 1 by cs is equal to 1 by c2 plus 1 by c3.
00:48
Here it is 1 by 4 plus 1 by 6 that is equal to 6 plus 4, 10 by 24.
00:56
This is 1 by cs and if we take reciprocal we get cs is equal to 24 by 10 microfarads.
01:07
Now the circuit becomes reduced like this that is so this is c1 and this will be the cs.
01:24
Here the two capacitance are in series so this will be 12 volts.
01:36
So if two capacitors are in series means sorry these are in parallel so here c1 and cs are parallel to each other...