00:01
Hello, here we have to solve the following problem.
00:02
Initially, in the shown circuit, the key is in position 2.
00:09
Let's make the sketch.
00:10
So i'm going to quickly sketch this battery, and the battery that's connected to r1.
00:16
Then there is a node 1, and the switch, and initially the switch is at the position 2.
00:38
So, first of all, we have to determine the current which flows when it's switched to the position 1.
00:46
In this case, the equivalent resistance is the sum of r1 and r2.
00:52
Therefore, this current equals to emf divided by r1 plus r2.
01:00
Then, in question 2, time becomes too long and that's why the current becomes 0, because there is no current through charged capacitor...