25 moles of O2?
Using the balanced equation, we can see that 2 moles of H2S react with 3 moles of O2. So, we can set up a proportion:
(2 moles H2S) / (3 moles O2) = (x moles H2S) / (3.25 moles O2)
Solving for x, we get:
x = (2 moles H2S * 3.25 moles O2) / 3
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