3 identical bulbs are connected in series and these together dissipate a power P. If now the bulbs are connected in parallel, then the power dissipated will be
Added by Zooko D.
Step 1
Given that the total power dissipated when the bulbs are connected in series is \( P_S = \frac{V^2}{3R} \), where \( R \) is the resistance of each bulb. Show more…
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