Question

3. If the mass of Earth is 5.98 ! 10$^{24}$ kg and the radius is 6.38 ! 10$^6$ m, the gravitational potential energy of a 1.2 ! 10$^3$-kg satellite located in an orbit 230 km above the surface of Earth is a. -1.1 ! 10$^4$ J b. -7.2 ! 10$^{10}$ J c. -2.1 ! 10$^{12}$ J d. -9.0 ! 10$^{12}$ J e. -2.1 ! 10$^{15}$ J 4. Looking at the diagram above, in which part of the orbit is the planet moving the fastest? a. A b. B c. C d. D e. none of the above

          3. If the mass of Earth is 5.98 ! 10$^{24}$ kg and the radius is 6.38 ! 10$^6$ m, the gravitational potential energy of a 1.2 ! 10$^3$-kg satellite located in an orbit 230 km above the surface of Earth is
a. -1.1 ! 10$^4$ J
b. -7.2 ! 10$^{10}$ J
c. -2.1 ! 10$^{12}$ J
d. -9.0 ! 10$^{12}$ J
e. -2.1 ! 10$^{15}$ J

4. Looking at the diagram above, in which part of the orbit is the planet moving the fastest?
a. A
b. B
c. C
d. D
e. none of the above

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3. If the mass of Earth is 5.98 ! 10^24 kg and the radius is 6.38 ! 10^6 m, the gravitational potential energy of a 1.2 ! 10^3-kg satellite located in an orbit 230 km above the surface of Earth is
a. -1.1 ! 10^4 J
b. -7.2 ! 10^10 J
c. -2.1 ! 10^12 J
d. -9.0 ! 10^12 J
e. -2.1 ! 10^15 J

4. Looking at the diagram above, in which part of the orbit is the planet moving the fastest?
a. A
b. B
c. C
d. D
e. none of the above

Added by Danish K.

Concepts of Physics

H. C. Verma 1st Edition

Chapter 11

Instant Answer

Solved by Expert Christopher Dzorkpata

08/17/2024

Step 1

98 \times 10^{24} \) kg - Radius of Earth, \( R = 6.38 \times 10^{6} \) m - Mass of the satellite, \( m = 1.2 \times 10^{3} \) kg - Height of the satellite above Earth's surface, \( h = 230 \) km = \( 230 \times 10^{3} \) m Show more…

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Transcript

00:01 Hello.

00:03 So here the potential energy u is going to be equal to gmm over r.

00:11 Let's say m1m2.

00:17 So let's look at this substitution here.

00:23 So of course potential energy is negative.

00:27 So this is going to be so our universal gravitational constant is 6 .674 times 10 to the negative.

00:43 The m1 is mass of the earth.

00:46 This is 5 .98 times 10 to the 24.

00:56 M2 is the mass of the satellite.

00:59 It's 1 .2 times 10 to the third.

01:06 So for the r, r is a distance that we have to be very careful with.

01:12 So r is going to be the height or the radius of the earth plus the height above the okay, so the height here.

01:40 So that's just going to be, so the radius of the earth is one point, oops, one second.

01:53 So the satellite is two 30 kilometers above the air.

01:58 So we have h so we just need to find r.

02:00 So yeah, r is 6 .38 times 10 to the 6 plus 2 .30 kilometers is that is times 10 to the third.

02:18 We need to cube all of this.

02:20 Excuse me.

02:22 Oh, this is just r.

02:23 So we just have this...

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