3. In the figure, ABCD is a square, F is a point lying on AB such that CF \ DE. If (AE = DE), find \angle ADF correct to the nearest degree.
Added by Jose Carlos H.
Close
Step 1
A-----E | | | | | | D-----C | F In the diagram, ABCD is a square and F is a point on AB such that CF is parallel to DE. AE is equal to DE. Show more…
Show all steps
Your feedback will help us improve your experience
Joseph P and 74 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
In △ABC, the angle bisectors drawn from vertices A and B intersect at point D. Find ∠ADB if ∠C = 130°.
Joseph P.
In the figure, m∠A = (2x + 3)° and m∠B = (3x - 18)°. Find the measure of each angle (in degrees) of ▱ABCD. a. Find x b. Find m∠A c. Find m∠B d. Find m∠C e. Find m∠D
Jerelyn N.
$\triangle A B F \sim \triangle C B D$ with obtuse angles at vertices $D$ and $F .$ If $\mathrm{m} \angle B=44^{\circ}$ and $\mathrm{m} \angle A: \mathrm{m} \angle C D B=1: 3,$ find $\mathrm{m} \angle A$. (FIGURE CAN'T COPY)
Similar Triangles
Proving Triangles Similar
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD