3 omega rl 5 omega 7v 2a 8 omega 4v a value of resistor rl...

3 $\Omega$ $R_L$ 5 $\Omega$ 7V 2A 8 $\Omega$ 4V a) Value of resistor, $R_L$, remainder of circuit to deliver maximum power? b) max power that a well-chosen resistor, $R_L$, can absorb to is closest to?

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00:01 Hello students, first to find the value of r, we need to short the circuit by maintaining short the voltage source and connecting 1 ampere load.

00:11 By doing so, we get this circuit.

00:15 Now applying loader analysis, we can write voltage at point a is 0, then voltage at b by 4 plus vb by 4 plus vb minus vc divided by 4 is equated to voltage va which is 0.

00:39 From this we obtain the equation 3 vb minus vc is equal to 0.

00:46 Consider this as equation 1.

00:48 Now for vc, we can write minus 1 plus vc minus vb divided by 4 plus vc minus v5 divided by 4 is equal to 0.

01:02 Here in the circuit we can observe that v5 is nothing but voltage vb.

01:09 Substituting as such we get 2 vc minus 2 vb is equal to 4.

01:16 This is equation 2.

01:20 To get simultaneous equation, multiply equation 1 by 2 so that we get 6 vb minus 2 vc is equal to 0.

01:33 Then second equation 2 vc minus 2 vb is equal to 0.

01:38 Here plus 2 vc and minus 2 vc get cancelled.

01:43 6 minus 2 will be 4 vb which is equal to 4.

01:51 So that vb will be equal to 4 by 4 which is equal to 1.

01:58 As vb equal to 1 volt, we get vc is equal to 3 vb which is equal to 3 volts.