The figure below shows a particle initially at point A traveling in the +x-direction. It turns in a circular path at constant speed until it is traveling in the +y-direction at point C. The quarter-circle arc from A to C is 205 m in length, and the particle moves from A to C in 30.0 s. Point B on the path is 35.0° below the x-axis. (a) What is the speed of the particle (in m/s)? m/s (b) What is the magnitude and direction of the acceleration when the particle is at point B? (Enter the magnitude in m/s² and the direction in degrees counterclockwise from the +x-axis.) magnitude m/s² direction ° counterclockwise from the +x-axis
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Given distance = 205 m and time = 30 seconds, we have: \[ \text{Speed} = \frac{205 \text{ m}}{30 \text{ s}} = 6.83 \text{ m/s} \] ** Show more…
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