00:01
The portion is c6h5 c2 is reacting with the br.
00:06
If c6h5 ch double bone ch2 is reacting with the br2, then we will get c6h5 ch5 chbi, ch2 br.
00:21
Now it is reacting with the ne nh2.
00:26
Nanh2 is the very strong base.
00:29
So a strong base can eliminate both the growing group.
00:32
Both of the roman root that's why 2 mole of nab will get eliminated and then we will get alky.
00:43
This alkyne is reacting with the ch3i further, not cs3i.
00:50
Here we can, here we is only 2 mole of an h2.
00:54
So one more is also remaining.
00:56
So nh2 minus will abstract this acidic hydrogen...