Question

3. $5p - rq = 3$ $3p - 5q = 7$ In the system of equations above, $r$ is a constant and $p$ and $q$ are variables. For what value of $r$ will the system of equations have no solution? A) $rac{5}{3}$ B) $rac{25}{3}$ C) $rac{3}{7}$ D) 5

          3. $5p - rq = 3$
$3p - 5q = 7$
In the system of equations above, $r$ is a constant and $p$ and $q$ are variables. For what value of $r$ will the
system of equations have no solution?
A) $rac{5}{3}$
B) $rac{25}{3}$
C) $rac{3}{7}$
D) 5

3. 5p - rq = 3
3p - 5q = 7
In the system of equations above, r is a constant and p and q are variables. For what value of r will the
system of equations have no solution?
A) rac53
B) rac253
C) rac37
D) 5

Added by Stephanie B.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Lauren Bernstein

Step 1

The left side of the equation contains the term 3sqr(r), which means that r must be a positive number. If r is negative or zero, the term 3sqr(r) would not be defined. Show more…

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3sqr(r) - 3 - 5q = 7 In the system of equations above, s is a constant and r and q are variables. For what value of r will the system of equations have no solution?