00:01
Okay, so we're going to do it from the question 3a.
00:05
So we can model this as a bernoulli trials.
00:16
And here the success probability is 3%.
00:21
And the probability that the first defective hard drive is the fifth.
00:27
Is 1 minus the success probability raised the 4 times p.
00:34
So you have a 0 .9.
00:38
7 to 4 times 0 .03.
00:47
And next, what constitutes a success in this situation? so the success is finding the defective.
01:00
See, what is the probability of success in the first attempt? so that's just going to be px equals 0, or px equals 1, let's say.
01:13
And that's just 3%, 0 .03 .d.
01:18
What is the probability that the first defective hard drive is the third unit tested.
01:25
So we need to have a 2 that is unsuccessful, and the third one is a success...