3. The generalised Laguerre differential equation is $xy''(x) + (\alpha + 1 - x)y'(x) + ny = 0$. (a) Substitute a solution of the form $y(x) = \sum_{k=0}^{\infty} a_k x^k$ into the equation and hence derive a recurrence relation for the coefficients $a_k$. Deduce that for positive integer $n$, $y(x)$ is a polynomial. (b) The Laguerre polynomials are given by $L_n^{(\alpha)}(x) = \sum_{k=0}^n (-1)^k \binom{n+\alpha}{n-k} \frac{x^k}{k!}$ Verify that these satisfy the recurrence relation you found in part (a).
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The term with x^k is: k(k-1)akx^k The term with x^(k-1) is: (a+1)akx^(k-1) The term with x^k-2 is: -akx^(k-2) So, the equation becomes: k(k-1)akx^k + (a+1)akx^(k-1) - akx^(k-2) + ny = 0 Now, let's collect the terms with the same power of x: x^k: k(k-1)ak Show more…
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