3. Use the HJ equation to solve for the trajectory of a projectile. The Hamiltonian is $H = \frac{(p_x^2 + p_y^2)}{2m} + mgy$. Using the HJ approach you should derive the usual formulas x(t) = v_0 \cos(\theta_0) t y(t) = v_0 \sin(\theta_0) - \frac{g}{2}t^2
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The Hamiltonian equation is given as p + H = KBu + 2m. Show more…
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