00:01
Hello students, let's look at the question.
00:02
Here, find linear and parabolic coefficient of dry oxidation at 1 ,000 degrees celsius and 1 ,000 degrees celsius is equals to 1 -273 kelvin.
00:19
B by a dry is equal to 3 .71 into 3 .71 into 10 to the power 6 micrometer upon hr.
00:41
Experimental minus 2 electrovalent is divided by 8 .617 multiply 10 to the power minus electrovalent is divided by 8 .617 multiply 10 to the power minus 5.
00:58
Electrovalent electrovolta k 1273 kelvin is a here b by a dry is equal to 0 .0 .45 micrometer upon r b dry b dry is equal to 772 micrometer square is divided by hr and exp that is experimental minus 1 .23 ev is divided by 8 .616.
02:02
7 into 10 to the power minus 5 ev by k and again it's multiply by 1 -2 -73 kelvin that is temperature and in bracket cold close b dry is equal to 0 .0104 micrometer square upon the oxide thickness, the oxide thickness at the end of the step is t .ox1 is equals to is equals to 0 .045 micrometer square upon r is divided by to 2 multiply 0 .0 .0.
03:04
1 .04 micrometer is divided by r.
03:11
Break it close and then this 1 plus 4 multiply 0 .045 micrometer is divided by r and whole square is divided by 0 .0 .0 .5 micrometer is divided by r and whole square is divided by 0 .0 .0 104 micrometer square is divided by r and here 1 r minus 1.
03:47
So this is the equation.
03:49
When we solve this t.
03:52
Ox1 is equal to 0 .72 micrometer.
03:57
Now we find coefficient for wet oxidation at wet oxidation at 1100 degrees celsius and that is equals to 1373 kelvin because temperature is in kelvin.
04:15
So it converted from degree celsius to kelvin...