Question

3.) You learned in Physics 221 that all conservative forces, F, have an associated potential energy, U, and they are related by the equation: $U(x) = - \int F(x)dx$ A a.) If the Coulomb force has an associated potential energy given by the expression: $F(r) = \frac{A}{r^2}$, what would be the corresponding expression for the force, U(r)? A is a constant. I must see your setup of your integral. Assume the constant of integration is zero. A b.) If the Coulomb force has an associated potential energy given by the expression: $F(r) = \frac{A}{r}$, what would be the corresponding expression for the force, U(r)? A is a constant. I must see your setup of your integral. Assume the constant of integration is zero.

          3.) You learned in Physics 221 that all conservative forces, F, have an associated potential energy, U, and they are related by the equation:
$U(x) = - \int F(x)dx$
A
a.) If the Coulomb force has an associated potential energy given by the expression: $F(r) = \frac{A}{r^2}$, what would be the corresponding expression for the force, U(r)? A is a constant. I must see your setup of your integral. Assume the constant of integration is zero.
A
b.) If the Coulomb force has an associated potential energy given by the expression: $F(r) = \frac{A}{r}$, what would be the corresponding expression for the force, U(r)? A is a constant. I must see your setup of your integral. Assume the constant of integration is zero.
        
Show more…
3.) You learned in Physics 221 that all conservative forces, F, have an associated potential energy, U, and they are related by the equation:
U(x) = - ∫ F(x)dx
A
a.) If the Coulomb force has an associated potential energy given by the expression: F(r) = (A)/(r^2), what would be the corresponding expression for the force, U(r)? A is a constant. I must see your setup of your integral. Assume the constant of integration is zero.
A
b.) If the Coulomb force has an associated potential energy given by the expression: F(r) = (A)/(r), what would be the corresponding expression for the force, U(r)? A is a constant. I must see your setup of your integral. Assume the constant of integration is zero.

Added by Jennifer D.

Close

University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
3.) You learned in Physics 221 that all conservative forces, F, have an associated potential energy, U, and they are related by the equation: U(x) = -∫ F(x) dx a.) If the Coulomb force has an associated potential energy given by the expression: F(r) = (A)/(r^2) what would be the corresponding expression for the force, U(r)? A is a constant. I must see your setup of your integral. Assume the constant of integration is zero. b.) If the Coulomb force has an associated potential energy given by the expression: F(r) = (A)/(r) what would be the corresponding expression for the force, U(r)? A is a constant. I must see your setup of your integral. Assume the constant of integration is zero.
Close icon
Play audio
Feedback
Powered by NumerAI
Jennifer Stoner Danielle Fairburn
Kathleen Carty verified

David Morabito and 50 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Key Concept
Premium Feature
Explore the core concept behind this problem.
Play button
Key Concept
Premium Feature
Explore the core concept behind this problem.
Your browser does not support the video tag.

*

Recommended Videos

-
problem-4-a-mysterious-force-has-been-discovered-in-nature-that-acts-on-all-particles-in-the-three-dimensional-space_-you-determine-that-the-force-is-always-pointed-away-from-definite-point-75675

Problem 4: A mysterious force has been discovered in nature that acts on all particles in three-dimensional space. You determine that the force is always pointed away from a definite point in space, which we can call the force center. The magnitude of the force has the following functionality: F = Ae^(-br), where r is the distance from the force center to any other point. Part (a) Write an expression for the potential energy U of a particle when it is at a distance D from the force center, assuming the potential energy to be zero when the particle is at infinity. Part (b) If D is measured in meters, then what must the units be for the proportionality constant A in order for the energy to be in Joules? Part (c) If D is measured in meters, then what must the units be for the constant b in order for the energy to be in Joules? Part (d) If the particle is at a distance of 0.46 m from the force center and the constants are A = 17 and b = 6, then what is the potential energy of that particle?

David M.

1-a-rod-of-negligible-thickness-lies-on-the-x-axis-with-one-end-atx-0-and-another-at-x-l-positive-charges-are-distributed-along-the-length-of-the-rod-according-to-the-linear-charge-density-a-21919

[1] A rod of negligible thickness lies on the x-axis with one end at x=0 and another at x=L. Positive charges are distributed along the length of the rod according to the linear charge density λ(x) = λ₀ x/L, with λ₀ > 0 as a constant. Point P on the x-axis is a distance x₀ away from the origin and is our point of observation. Assume x₀ > L. (A) Sketch the situation described above, paying attention to approximate charge distribution at the two ends of the rod. Clearly show where point P is with respect to the rod. (B) Calculate the electric field Ē at location P. This calculation involves multiple steps because the charges are not point charges but are distributed over a length! For point charges we can write down E=kq/r² but for distributed charges we have to first reduce the problem to point charge and then count up to include contribution of all charges. Hint: (i) First set up an expression for dĒ, the electric field due to an infinitesimally small amount of charge on the rod and show that dE = kλ₀/L * x dx / (x₀-x)². For inspiration (note: situation is different there) see Example 21-11 in the textbook. (ii) Next, argue that the total electric field at location P is given by Enet = kλ₀/L ∫₀ᴸ x dx / (x₀-x)². The physics problem is now a calculus problem where you have to solve the integral! (iii) If given that the indefinite integral ∫ z dz / (a-z)² = a/(a-z) + ln(a-z) + constant, where a>0, calculate the electric field Enet at P. (iv) What is the direction of Enet? (C) Calculate in terms of λ₀, L and other constants, the total charge Q on the rod. Hint: by definition, the total charge=∫ λ(x) dx, with appropriate limits on the integral. [2] In the figure, an object of mass m and positive charge q is suspended in static equilibrium due to the combined effect of tension T in the string attached to the object and force F due to an inclined E field (inclined at 30° to the horizontal) in space. (A) Calculate the magnitude of Ē, in terms of m, q, and numerical constants. (B) Find the magnitude of T in terms of the same quantities. Take g= 10 m/s².

Timothy J.

review-constants-coulomb-law-for-the-magnitude-of-the-force-f-between-two-particles-with-charges-q-and-separated-by-distance-d-is-part-a-ifl-klql-what-is-fnct-3r-the-x-component-of-the-net-f-80245

Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is |F| = K |QQ'| / d^2 where K = 1 / (4πε0) and ε0 = 8.854 × 10^−12 C^2/(N·m^2) is the permittivity of free space. Consider two point charges located on the x axis: one charge q1 = −12.0 nC is located at x1 = −1.700 m; the second charge, q2 = 39.5 nC, is at the origin (x = 0). Part A What is (F_net)_x, the x-component of the net force exerted by these two charges on a third charge q3 = 51.5 nC placed between q1 and q2 at x3 = −1.205 m? Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures.

Adi S.


*

Recommended Textbooks

-
University Physics with Modern Physics

University Physics with Modern Physics

Hugh D. Young 14th Edition
achievement 1,294 solutions
Physics: Principles with Applications

Physics: Principles with Applications

Douglas C. Giancoli 7th Edition
achievement 1,852 solutions
Fundamentals of Physics

Fundamentals of Physics

David Halliday, Robert Resnick , Jearl Walker 10th Edition
achievement 1,001 solutions

*

Transcript

-
00:01 In this problem, you're given a force magnitude and your tunnel is always pointing away from some point in space.
00:10 So if this is the point you want to look at the force on an object here, that force is always away from it.
00:16 Always outward along the radio direction.
00:19 You might say, i've never seen anything like this before.
00:21 Yes, you have.
00:22 Just not outward.
00:23 You saw it inward.
00:24 Think of universal gravitation, always toward the center of the earth.
00:29 So you've seen it.
00:29 And you also knew that that force, this is not one of our squared.
00:36 That force was conservative.
00:38 This force also is conservative.
00:39 That's why they're asking you to get a potential energy function.
00:42 We could go through a lot.
00:43 We could do a whole other problem analyzing this in the same way to justify that.
00:51 That it is conservative that you can write a potential energy.
00:55 But we don't need to do that here.
00:58 So let us look at this.
01:00 Delta u the changing potential energy is defined so this is u r i'm going to go from infinity to r and that's defined as minus the integral from infinity to r f dot d r prime i have an r here i want to have a different symbol here so we don't have any confusion just a dummy index i'll be able so it's okay don't be bothered by that.
01:34 Now, dr prime vector is dr prime, r hat prime.
01:41 Just think of this as the r prime now.
01:44 So, anytime i dot a vector with a unit vector, i get the component in that direction.
01:49 So it becomes minus infinity to r, f, r prime, dr prime.
01:57 That's what i get.
01:59 Now, as i have drawn, that is a positive rp.
02:04 Prime components.
02:06 It's in the positive r hat prime direction.
02:10 So now i can put in, this is minus infinity to r, a, e minus b, r prime, d, r prime.
02:24 And now we can do the integral.
02:26 This is minus a, and the integral of e to minus b r prime is minus b, e to minus b, and our limits infinity to r.
02:38 And we can clean this up a little bit.
02:42 A over b, eta minus b r prime, infinity to r.
02:50 And i'll put in our limits.
02:52 A over b, e minus br, minus e to minus b times infinity, but that's one over an extremely large number.
03:04 Back to the infinite.
03:05 This term does not contribute.
03:07 This term is gone.
03:08 And let's not forget they tell us also that you, we're to take you at infinity to be zero.
03:12 So this is ur now.
03:17 So it becomes a over b, e minus b, r.
03:22 That's the functional form.
03:24 Now they ask us to put it right for position d.
03:28 R is equal to d.
03:29 So we would write u at d, a, e minus b, d over b...
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever