00:01
We are given a table here, so we have to complete the graph here.
00:04
So we have the frequency and the age, the clauses.
00:09
So we have 40 here, and 25, 30, 15, and 10.
00:16
And what about the relative frequency? to get the relative frequency, i'm going to just divide the subgroup frequency by the total frequency, which is 120 here.
00:27
This is 1 over 3 which is equal to 0 .33 and 25 over 120.
00:36
This is 25 over 120 which is 0 .21 and this is 30 over 120 which is 0 .20 which is 0 .25.
00:47
This is 15 over 120.
00:49
That should be this is 15 over 120 which is 0 .20 which is 0 .20 let's say 13 right and 10 over 120 this is 10 over 120 which is 0 .08 so this is 0 .0 let me check 0 8 great so we got the relative frequency here and the next one so this is part a part b identify the lower class limits the upper class limit so the lower class limit here which is so the lower class limits are 15, 26, 37, 48 and 59.
01:36
So for the upper class limits, that would be 25, 36, 47, 58 and 69.
01:47
And for part d, the class midpoints.
01:51
So for the midpoint, i'm going to just add 15 and 25 and divided by 2, which which is equal to this is 20 so let me just write here the mid points this is 20 so the class width here is 11 i'm going to just add 11 31 this is 42 add 11 53 add 11 64 great we got the mid points here and the e the class width so for the class width i can just subtract the lower class limit from the other class limit the successive class limit here this is 26 minus 15 which is 15 so the 15 is the class width here and what about the histogram for the frequency distribution table here we have to just draw the histogram let me just draw it let's say this is the frequency axis and we have the x value axis here this is the age by the way so what we have here, we have 15 and 26.
03:00
Let me just, this is a broken data.
03:02
This is 15, 26, 37, 48.
03:09
This is 59 and then 69...