300 mL of 0.05 M ammonia solution, where the density of the solution is 0.88 g/mL. What is the number of moles of ammonia? What is the weight (in grams) of ammonia? What is the molality of the solution?
Added by Sergio S.
Step 1
Given: Volume (V) = 0.3 L, Molarity (C) = 0.05 mol/L Number of moles of ammonia = C * V Number of moles of ammonia = 0.05 mol/L * 0.3 L Number of moles of ammonia = 0.15 mol Show more…
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