3.02 moles of an ideal gas are compressed isothermally at a temperature of \( 21.6^{\circ} \mathrm{C} \) in a reversible process. If \( 809 \mathrm{~J} \) of work are done on the gas in this process, what is the change in entropy of the gas?
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Since the temperature is given in Celsius, we first need to convert it to Kelvin for our calculations. The conversion formula is \( T(K) = T(^\circ C) + 273.15 \). \[ T = 21.6^\circ C + 273.15 = 294.75 \, K \] Show more…
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