00:01
All right, so we are doing this long division problem.
00:02
I went ahead and set it up in our normal division kind of setup.
00:07
The way we do long division for polynomials is we look at kind of the first number or the first term of each thing and we want those to match exactly.
00:19
So i'm thinking to myself, what do i have to multiply x squared by to get it to equal x to the fifth? x squared times x to the fifth.
00:31
So i'm going to put that x to the third up on the top and then we are going to multiply everything in our thing dividing the x squared plus 3x plus 1 by x to the third and we're going to subtract it from our equation.
00:45
So x squared times x to the third is x to the fifth.
00:50
3x times x to the third is 3x to the fourth and then 1 times x to the third is just x to the third.
00:59
So i multiplied everything like that and now i am doing this subtraction problem.
01:04
This negative is on the outside of the set of parentheses so it has to distribute to everything on the inside.
01:11
So really we're doing minus x to the fifth minus 3x to the fourth and minus x to the third.
01:19
Let's match up.
01:20
We have x to the fifth minus x to the fifth...