00:01
We are given an aluminum strut whose thickness is given that is equals to 10 millimeter has a cross sectional area which is shown here which is subjected to a shear of voltage that is equals to 80 kilo newton.
00:12
So we have to determine the shear flow at the point a and b.
00:17
So this is the figure from here.
00:21
So this is our given figure.
00:26
Let's say we are considering this is the reason 1, this is the reason 2, this is the reason 3, this is the reason 4 and this from here is the reason 5.
00:39
So this is given that is equals to 60, this is given that is equals to 40, this distance is given that is 27 .72.
00:46
So we have x axis which is goes through the base and the y axis goes through the symmetry to the shape.
00:53
So x bar is equals to 120 that is divided by 2 that is equals to 60 millimeter.
00:59
We have to find out the value of y dash.
01:01
So if you are considering about a1, so a1 from here is equals to 40 which is multiplied by the 10 that is equals to 400.
01:09
So y1 in this case is equals to 5 millimeter.
01:11
A2 is equals to 40 again multiplied by the 10 that is again equals to 400 millimeter, y2 become equals to 30 millimeter.
01:20
A3 from here is equals to 60 multiplied by the 10 that is equals to 600.
01:26
So y3 from here is equals to 50, 5 millimeter.
01:29
A4 is equals to 40 which is multiplied by the 10 that is equals to 400.
01:35
So y4 is equals to 30 millimeter.
01:38
A5 is equals to 40 which is multiplied by the 10 that is equals to 400...