Question

31.31. In an $L-R-C$ series circuit, $R=300 \Omega, L=0.400 \mathrm{H},$ and $C=6.00 \times 10^{-8} \mathrm{F}$ . When the ac source operates at the resonance frequency of the circuit, the current amplitude is 0.500 $\mathrm{A}$ . (a) What is the voltage amplitude of the source? (b) What is the amplitude of the voltage across the resistor, across the inductor, and across the capacitor? (c) What is the average power supplied by the source?

          31.31. In an $L-R-C$ series circuit, $R=300 \Omega, L=0.400 \mathrm{H},$ and
$C=6.00 \times 10^{-8} \mathrm{F}$ . When the ac source operates at the resonance
frequency of the circuit, the current amplitude is 0.500 $\mathrm{A}$ . (a) What
is the voltage amplitude of the source? (b) What is the amplitude
of the voltage across the resistor, across the inductor, and across
the capacitor? (c) What is the average power supplied by the
source?

Added by Brandon B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Penny Riley

12/10/2021

Step 1

Given: $I = 0.500 \, A$, $R = 300 \, \Omega$ Using Ohm's Law, $V = I \times R$ $V = 0.500 \, A \times 300 \, \Omega = 150 \, V$ Show more…

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31.31. In an $L-R-C$ series circuit, $R=300 \Omega, L=0.400 \mathrm{H},$ and $C=6.00 \times 10^{-8} \mathrm{F}$ . When the ac source operates at the resonance frequency of the circuit, the current amplitude is 0.500 $\mathrm{A}$ . (a) What is the voltage amplitude of the source? (b) What is the amplitude of the voltage across the resistor, across the inductor, and across the capacitor? (c) What is the average power supplied by the source?