00:01
Okay, in this example, we're looking ahead to a reaction that you will see later in the textbook, and what we've got is 1 -3 -prope -diene, or prope -di -en, reacting with this alpha -beta unsaturated ester.
00:29
And we're asked to show the curved arrow mechanism for the combination of a and b to form c.
00:35
And this might not be immediately obvious, but i think a little color coding can help.
00:45
Note that do the dye in blue.
00:54
Okay.
00:55
And then we'll do this molecule in green.
01:03
And hopefully we can see then how these must have come together.
01:10
So to the left of this carbonyl, we've got a two carbon chain.
01:17
Right so this needs to be two or it could go two right we don't really know yet that's okay um but then we can also look at this molecule here and it's like okay well we have to have a three carbon chain here um so maybe it could be one two three you know or perhaps it could be one two three we don't really know yet but that's basically how you would deconstruct this i'll tell you right now that the way it's actually done is that this bond came from the alpha beta unsaturated ester and these three carbons came from the dyeing.
02:06
Okay.
02:07
And the new bonds that we formed were this bond and this bond.
02:11
And i'll show you how those bonds are formed.
02:13
Okay.
02:15
So if i take this, hopefully i can rotate in.
02:23
Yeah.
02:30
This is a reaction that you will see later in the book.
02:33
As i said, the curved arrows are as follows.
02:37
We form like a bond here, right? that's how we draw that.
02:45
And we form a bond here.
02:48
That's how we draw that.
02:52
And then this bond moves to the back.
02:56
Yeah, pretty weird, but that's how it's drawn.
02:59
Okay? another way to draw it would be a little more direct where you point at the carbons.
03:08
Either way it will work.
03:12
In either case, that's the curved arrow mechanism...