Question

330. A loss under a liability policy is modeled by an exponential distribution The insurance company will cover the amount of that loss in excess of a deductible of 2000. The probability that the reimbursement is less than 6000, given that the loss exceeds the deductible, is 0.50. Calculate the probability that the reimbursement is greater than 3000 but less than 9000, given that the loss exceeds the deductible. 0.28 0.35 0.50 0.65 0.72

          330.
A loss under a liability policy is modeled by an exponential distribution The insurance company will cover the amount of that loss in excess of a deductible of 2000. The probability that the reimbursement is less than 6000, given that the loss exceeds the deductible, is 0.50.
Calculate the probability that the reimbursement is greater than 3000 but less than 9000, given that the loss exceeds the deductible.
0.28 0.35 0.50 0.65 0.72
        
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Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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330. A loss under a liability policy is modeled by an exponential distribution The insurance company will cover the amount of that loss in excess of a deductible of 2000. The probability that the reimbursement is less than 6000, given that the loss exceeds the deductible, is 0.50. Calculate the probability that the reimbursement is greater than 3000 but less than 9000, given that the loss exceeds the deductible. 0.28 0.35 0.50 0.65 0.72
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Transcript

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00:01 In this question we are given that the value of x is 50 and here the sample size is equal to 190.
00:12 P is equal to proportion is 20%, which is equal to 2500 as 0 .20.
00:25 So 1 minus p the probability for q will be 1 minus 0 .20 which is equal to 0 .80 which is equal to 0 .80.
00:34 0.
00:36 So now let's solve our first part of the question.
00:38 Here we will set our hypothesis first.
00:42 So hypothesis for this question are our null hypothesis, ho, is to peel less than or equal to 0 .20.
00:56 And our alternative hypothesis here, so p is greater than 0 .20.
01:02 And here we need to check for the right tamed test for the given hypothesis.
01:15 And after that, we will find our party solution for this same question.
01:21 Here you will find i will refer n into p which will be value of n is 190 and value for p is 0 .20.
01:35 So we have to multiply these two values which are equal to 38.
01:41 And on the next step we will find n include 1 minus p.
01:46 So value of n is 190 multiplied by 1 minus 0 .20...
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