Question

(#332423) (Gauss's Law w/ Charge Distributions) An infinite charged wire with charge per unit length $\lambda$ (that is, 1 m of the wire contains $\lambda$ Coulombs of electric charge) lies along the central axis of a cylindrical surface of radius $r$ and length $l$. What is the flux through the surface due to the electric field of the charged wire? Select the correct answer O $\frac{\lambda}{\epsilon_0}l$ electrons O $\frac{\lambda}{2\pi\epsilon_0}l$ electrons O $\frac{\lambda}{l\epsilon_0}$ electrons O $\frac{\lambda}{\epsilon_0}l^2$ electrons O $\frac{\lambda^2}{\epsilon_0}l$ electrons

          (#332423) (Gauss's Law w/ Charge Distributions)
An infinite charged wire with charge per unit length $\lambda$ (that is, 1 m of the wire contains $\lambda$ Coulombs of electric charge) lies along the central axis of a cylindrical surface of radius $r$ and length $l$. What is the flux through the surface due to the electric field of the charged wire?
Select the correct answer
O $\frac{\lambda}{\epsilon_0}l$ electrons
O $\frac{\lambda}{2\pi\epsilon_0}l$ electrons
O $\frac{\lambda}{l\epsilon_0}$ electrons
O $\frac{\lambda}{\epsilon_0}l^2$ electrons
O $\frac{\lambda^2}{\epsilon_0}l$ electrons

Show more…

332423 gausss law w charge distributions an infinite charged wire with charge per unit length lambda that is 1 m of the wire contains lambda coulombs of electric charge lies along the centra 59768

Added by Erica H.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Suhas Katkar

10/24/2020

Step 1

Mathematically, $$\Phi_E = \oint \vec{E} \cdot d\vec{A} = \frac{Q_{enc}}{\epsilon_0}$$ In this case, the charge enclosed by the cylindrical surface is the charge per unit length $\lambda$ multiplied by the length $l$ of the wire within the cylinder. $$Q_{enc} = Show more…

Show all steps

lock

Thanks for your feedback!

(#332423) (Gauss's Law w/ Charge Distributions) An infinite charged wire with charge per unit length $\lambda$ (that is, 1 m of the wire contains $\lambda$ Coulombs of electric charge) lies along the central axis of a cylindrical surface of radius $r$ and length $l$. What is the flux through the surface due to the electric field of the charged wire? Select the correct answer O $\frac{\lambda}{\epsilon_0}l$ electrons O $\frac{\lambda}{2\pi\epsilon_0}l$ electrons O $\frac{\lambda}{l\epsilon_0}$ electrons O $\frac{\lambda}{\epsilon_0}l^2$ electrons O $\frac{\lambda^2}{\epsilon_0}l$ electrons

Play audio

Feedback

Powered by NumerAI

Suhas Katkar and 89 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Recommended Videos

Recommended Textbooks

Transcript

Ace is your personal tutor. It breaks down any question with clear steps so you can learn.

Start Using Ace

Continue solving this problem

Create a free account to:

View full step-by-step solution
Ask follow-up questions with Ace AI
Save progress and study later