Question

13-38 The following equation is an approximation of the gas force over 180° of crank angle. $F_s = \begin{cases} F_{s_{max}} \sin[ (\omega t/\beta)(\pi/2)], & 0 \le \omega t \le \beta \\ F_{s_{max}} \{1 + \cos[x(\omega t - \beta)/(\pi - \beta)]\}/2, & \beta < \omega t \le \pi \end{cases}$ Using this equation with $\beta = 15^\circ$ and $F_{s_{max}} = 1200$ lb, calculate and plot the approximate gas torque for $r = 4$ in and $l = 12$ in. What is the total energy delivered by the gas force over the 180° of motion? What is the average power delivered if the crank rotates at a constant speed of 1500 rpm?

          13-38 The following equation is an approximation of the gas force over 180° of crank angle.
$F_s = \begin{cases} F_{s_{max}} \sin[ (\omega t/\beta)(\pi/2)], & 0 \le \omega t \le \beta \\ F_{s_{max}} \{1 + \cos[x(\omega t - \beta)/(\pi - \beta)]\}/2, & \beta < \omega t \le \pi \end{cases}$
Using this equation with $\beta = 15^\circ$ and $F_{s_{max}} = 1200$ lb, calculate and plot the approximate gas torque for $r = 4$ in and $l = 12$ in.
What is the total energy delivered by the gas force over the 180° of motion? What is the average power delivered if the crank
rotates at a constant speed of 1500 rpm?

$13-38 The following equation is an approximation of the gas force over 180° of crank angle. Fs = Fsmaxsin[ (ω t/β)(π/2)], 0 ≤ω t ≤β Fsmax{1 + cos[x(ω t - β)/(π - β)]}/2, β < ω t ≤π Using this equation with β = 15^∘ and Fsmax = 1200 lb, calculate and plot the approximate gas torque for r = 4 in and l = 12 in. What is the total energy delivered by the gas force over the 180° of motion? What is the average power delivered if the crank rotates at a constant speed of 1500 rpm?$

Added by Christine G.

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