34% of working mothers do not have enough money to cover their health insurance deductibles. You randomly select six working mothers and ask them whether they have enough money to cover their health insurance deductibles. The random variable represents the number of working mothers who do not have enough money to cover their health insurance deductibles. Complete parts (a) through (c) below. (a) Construct a binomial distribution using n = 6 and p = 0.34. x P(x) 0 1 2 3 4 5 6 (Round to the nearest thousandth as needed.)
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A binomial distribution is a probability distribution that describes the number of successes in a fixed number of independent Bernoulli trials with the same success probability. In this case, the "success" is defined as a working mother not having enough money to Show more…
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32% of working mothers do not have enough money to cover their health insurance deductibles. You randomly select six working mothers and ask them whether they have enough money to cover their health insurance deductibles. The random variable represents the number of working mothers who do not have enough money to cover their health insurance deductibles. Complete parts (a) (a) Construct a binomial distribution using n=6 and p=0.32. x P(x) 0 1 2 3 4 5 6 (Round to the nearest thousandth as needed.)
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38% of working mothers do not have enough money to cover their health insurance deductibles. You randomly select six working mothers and ask them whether they have enough money to cover their health insurance deductibles. The random variable represents the number of working mothers who do not have enough money to cover their health insurance deductibles. Complete parts (a) through (c) below. (a) Construct a binomial distribution using n=6 and p=0.38. x P(x) 0 nothing 1 nothing 2 nothing 3 nothing 4 nothing 5 nothing 6 nothing (Round to the nearest thousandth as needed.)
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Apply Procedure 6.3 on page 289 to approximate the required binomial probabilities. Lightning-Induced Fatalities. As reported in an issue of Weathenvise, according to the National Oceanic and Atmospheric Administration, people at ballparks and playgrounds are in more danger of being struck by lightning than are those on golf courses. Of lightning-induced fatalities, $3.9 \%$ occur on golf courses. What is the probability that, of 250 randomly selected lightning-induced fatalities, the number occurring on golf courses is a. exactly $4 ?$ b. between 4 and $10,$ inclusive? c. at least $10 ?$ d. Comment on the accuracy of the normal approximation in this case.
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