Question

a = 3.4 x 10$^{-39}$ Cm$^2$/V at 10$^\circ$C a = 3.0 x 10$^{-39}$ Cm$^2$/V at 60$^\circ$C Determine: a) The permanent dipole moment, expressed in debye units b) The electronic polarizability c) The atomic polarizability For your calculations assume that the atomic polarizability is 10% of the electronic polarizability.

          a = 3.4 x 10$^{-39}$ Cm$^2$/V at 10$^\circ$C
a = 3.0 x 10$^{-39}$ Cm$^2$/V at 60$^\circ$C
Determine:
a) The permanent dipole moment, expressed in debye units
b) The electronic polarizability
c) The atomic polarizability
For your calculations assume that the atomic polarizability is 10% of the
electronic polarizability.

a = 3.4 x 10^-39 Cm^2/V at 10^∘C
a = 3.0 x 10^-39 Cm^2/V at 60^∘C
Determine:
a) The permanent dipole moment, expressed in debye units
b) The electronic polarizability
c) The atomic polarizability
For your calculations assume that the atomic polarizability is 10% of the
electronic polarizability.

Added by Beatriz R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Penny Riley

Step 1

4 x 10^-39 Cm^2/V at 10°C Electric field = 1 V/cm (since the units cancel out) Substituting the values into the formula: Permanent dipole moment (in debye) = (3.4 x 10^-39 Cm^2/V) x (1 V/cm) Simplifying the units: Permanent dipole moment (in debye) = 3.4 x 10^-39 Show more…

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3.4 x 10^-39 Cm^2/V at 10Â°C 3.0 x 10^-39 Cm/V at 60Â°C Determine: a) The permanent dipole moment, expressed in debye units b) The electronic polarizability c) The atomic polarizability For your calculations, assume that the atomic polarizability is 10% of the electronic polarizability.