Question

A 350-kg chandelier is suspended from vertical steel cable. The cable is 5.9 m long. Assume a safety factor of 8.5. The elastic modulus for steel is $2.0 imes 10^{11} ext{ N/m}^2$, and tensile strength for steel is $5.0 imes 10^8 ext{ N/m}^2$. Part A What is the minimum cross-sectional area required of the cable? Express your answer to two significant figures and include the appropriate units. $A_{min} = $ Part B How much does the cable elongate? Express your answer to two significant figures and include the appropriate units. $Delta L = $

          A 350-kg chandelier is suspended from vertical steel cable. The cable is 5.9 m long. Assume a safety factor of 8.5. The elastic modulus for steel is $2.0 	imes 10^{11} 	ext{ N/m}^2$, and tensile strength for steel is $5.0 	imes 10^8 	ext{ N/m}^2$.
Part A
What is the minimum cross-sectional area required of the cable?
Express your answer to two significant figures and include the appropriate units.
$A_{min} = $
Part B
How much does the cable elongate?
Express your answer to two significant figures and include the appropriate units.
$Delta L = $

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A 350-kg chandelier is suspended from vertical steel cable. The cable is 5.9 m long. Assume a safety factor of 8.5. The elastic modulus for steel is 2.0 imes 10^11 ext N/m^2, and tensile strength for steel is 5.0 imes 10^8 ext N/m^2.
Part A
What is the minimum cross-sectional area required of the cable?
Express your answer to two significant figures and include the appropriate units.
Amin =
Part B
How much does the cable elongate?
Express your answer to two significant figures and include the appropriate units.
Delta L =

Added by Diane T.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adriano Chikande

04/26/2022

Step 1

Given: P = 350 kg * 9.81 m/s^2 = 3435 N sigma = 5.0 x 10^8 N/m^2 / 8.5 = 5.88 x 10^7 N/m^2 Using the formula, we have: 5.88 x 10^7 N/m^2 = 3435 N / A Solving for A: A = 3435 N / 5.88 x 10^7 N/m^2 A = 5.84 x 10^-5 m^2 Show more…

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A 350-kg chandelier is suspended from vertical steel cable. The cable is 5.9 m long. Assume a safety factor of 8.5. The elastic modulus for steel is 2.0 x 10^11 N/m^2 and tensile strength for steel is 5.0 x 10^8 N/m^2. Part A What is the minimum cross-sectional area required of the cable? Express your answer to two significant figures and include the appropriate units. A_min Part B How much does the cable elongate? Express your answer to two significant figures and include the appropriate units. ΔL

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