00:01
Here we are given the value of d that is equals to 12 millimeter and the value of g is given that is equals to 6 millimeter.
00:08
The value of e is equals to 200 gigapascal and that of land is given that is equals to sorry this is load.
00:19
So the load is given that is equals to 4 .2 kilo newton.
00:23
So from the given figure we can draw it it's fbd.
00:27
So fbd of the figure is let's say we are given the two points.
00:31
This is the point a from here the point b a normal tension t is acting in between this and the distance between the a and the point where the tension is acting is 1 .5 meter and the distance between the tension and the point t is 4 .5 meter.
00:48
A normal reaction to ab is acting which is at a distance x from the b which is 4 .5 kilo newton from here.
00:59
So we can say that summation of ma from here is equals to 0 which is acting towards the positive side.
01:07
So from the fbd we can say that 1 .5 of t minus 4 .5 that is multiplied by the 6 minus x is equals to 0.
01:15
So this from here is equals to 1 .5 of t minus 27 plus 4 .5 x that is equals to 0.
01:23
Solving this term from here we get the value as 1 .5 t plus 4 .5 x that is equals to 27.
01:31
Let's say this is the equation number 1.
01:33
1 from here and now we are given the another condition...