00:01
According to the question, we have to calculate the molality for two parts.
00:04
In first part, the mass of h2 -s -o -4, that is sulfuric acid given, is equal to 583 gram, while the mass of water, that is solvent mass, is equal to 1 .50 kg.
00:20
And we have to calculate the molality of h -2 -s -o -4, that is, the molality or you can say concentration of, h2 -s -o -4 in terms of molality.
00:32
This is our target.
00:34
Now the molecular weight of h2s -o -4 is equal to 98 .079 gram per mole and the formula of molality, this is mass.
00:47
Now the formula of molality of h2 -s -o -4 is equal to, molality is equal to number of moles of solute divided by mass of solvent.
01:00
Mass of solvent must be in kg.
01:03
Now number of solute can be mass of solute divided by molecular weight of solute multiply by mass of solvent in kg.
01:16
By putting all the values, we will get the molality of h2 -s -o -4...