00:01
In this problem, we're given that 3 eighths of the people attending the fair are children.
00:06
We are also given that 3 .4ths of the remaining people attending the fair are men.
00:11
We know that since 3 .8s are children, the remainder of the amount of people is 5 .8s.
00:17
So 3 .4ths of 5 .8s of the people are men because 5 .8s plus 3 .8s is 8ths or 100%.
00:27
And then we are given the last statement, which is that 140 more children are there than women.
00:35
To solve this problem, we're going to connect our first and second statements together first.
00:40
So we know that three -eighths of the people are children, and we know that three -fourths of five -eighths are men.
00:47
So let's discover how many men there are.
00:51
So we can say three -fourths times five -eighths are men.
00:59
So we get a grand total of 15, 30 seconds are men.
01:04
And we know if we can multiply 3 eighths by 4 over 4 to get a common denominator we get 12 30 seconds now that if we add these two together we get the amount of people who are women so 12 plus 15 is 27 over 30 seconds which means that the remainder of people who are women if we do 32 minus 27 over 32 we get the amount of people who are women is is five 30 seconds okay so we know that 27 30 seconds are children we know that 15 30 seconds are men and we know that 5 30 seconds are a woman now using this we can discover the total number by knowing that 140 more children showed up than woman to relate these two pieces of information, let's convert our value of children, men, and woman into percentages.
02:25
So the percentage of children at the carnival or at the fun fair is 27 divided by 32 or my stylus isn't working...