39 inanuclear reactor neutrons released by nuclear fission...

39. In a nuclear reactor, neutrons released by nuclear fission must be slowed down before they can trigger additional reactions in other nuclei. To see what sort of material is most effective in moderating (slowing down) neutrons, calculate the ratio of the neutron's final kinetic energy to its initial kinetic energy, Kf/Ki, for a head-on elastic collision with each of the following stationary target particles: (Note: The mass of a neutron, m, is 1.009u, where the atomic mass unit, u, is defined as follows: u = 1.66 * 10^-27 kg.) (a) An electron (M = 5.49 * 10^-4u) (b) A proton (M = 1.007u) (c) The nucleus of a lead atom (M = 207.2u).

Transcript

00:01 Let's start the explanation of the question.

00:07 So you know that the one value which is given and the atomic mass and atomic number which is also given, 235 and 92 plus the n which is 1 and 0.

00:30 So on the other hand, we can rect it, which is b, a, b, a, and we can say that which is 144.

00:49 And 56 plus the k r the kr which is 36 and 89 and 89 so plus we can say that which is the n 3 -0 3 1 and 0 so on the other hand we will start the part a so we can say that in part a the 0 the 0 you which is equal to m into we know the value of atomic mass and atomic number of you which is 235 over 92 plus m into m which is 1 and 0 minus into m and we know the value of b a the atomic mass and atomic number of b a which is 144 and 56 14 and 56 plus now we write down the atomic mass and atomic number of k r which is 89 and 36 89 and 36 plus 3m 3m into and which is 1 and 0 so actually this is our complete equation so now moving on the next step we have in 2 and step we can say that in next step we can say that minus two three minus two three five point zero plus three nine three zero new plus one point zero double eight zero double eight six me into u minus into u minus into u minus one 144 144 .922 and 144192 so on the other hand we can say that 953 mu minus 88.

04:32 98 .917630 917630 new new which is minus minus 3m into 1 .8 .8 .917630 mu which is minus 3 into 1 .8 1 .8086 into 1 .8086 so we can say that which is the bracket close so the answer of this equation which is equal to 0 .1860 mu so on the other hand actually this is the first value we have required this so on the other hand we can say that the value of q the value of q which is equal to 0 .1860 mu into 9931m .5 m e.

05:54 Which is divided by u so the answer which is equal to 173 .0 .3m...

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