00:01
High students in the question they are given compound a for the compound a in the presence of h2 s4 and h.
00:10
H4 we are we need to draw the mechanism of the substitution products and the elimination products.
00:20
The structure of the compound is like this.
00:25
Here is the subjuncts 1, methyl group and also oh2.
00:33
These are the subcants present in the compound a.
00:38
In the first step, react with h2 as so forth.
00:42
Forming this vogue is converted into h2o, that is bollis h2 and remaining groups are same, no changes occur in other subcontents.
01:09
Minus h2o, carbocatal is forming.
01:19
This is the carbocatinis form.
01:27
This is the tertiary carbocatium.
01:33
This tertiary carboxyam is react with in the presence of mh4 plus vr minus this.
01:41
Mhx4 plus vr minus the bromine is attached to the positive carbonine and the subteration products are as follows.
02:04
Here is methyl group at the place of carburetane.
02:15
Bromene is attached.
02:21
This is the one structure and the other one is in the opposite side gromini is attached.
02:37
Gromene.
02:43
This is the substitution products of the compound way.
02:50
In this way the mechanism has happened and the elimination products are in the presence of nh4 f .r...