00:01
Hello students let's begin with this question.
00:02
In this question one reaction is given so this is the reaction aucl3 in the presence of water it will dissociate to form au3 positive ion plus 3 cl negative ions.
00:18
So in this question we have to find out the q value here this q is equals to the ionic product this is the ionic product solubility constant.
00:34
So this thing we have to find out in this question.
00:38
So here in the question the concentration of au3 positive is given which is equals to here it is given that 2 .1 into 10 raised to power 8 molar it is present in the 292 ml.
00:55
Then the concentration of cl negative ion is given so this is equals to 1 .8 into 10 raised to power minus 6 molar in 123 ml.
01:10
So firstly we have to find out the concentrations of the both the ions in the given volume.
01:16
So firstly the concentration of the au3 positive ion is equals to 292 ml that is multiplied by 2 .1 into 10 raised to power minus 8 molar this will be divided by the total volume.
01:30
So total volume is 292 ml plus 123 ml.
01:35
So now when we solve this we get the concentration of au3 positive which is equals to 0 .0000001478 molar...