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3. (Program) a. Create an operator function for the Date class in Class 11.1 that compares two Date objects and returns a Boolean value of true if the first date is larger than the second; otherwise, it should return a false value. The "larger than" algorithm for this comparison operator function is the following: Accept one date as the current object being evaluated and a second date as an argument Determine the later date with the following procedure: Convert each date to a long integer value in the form yyyymmdd, using the algorithm in Exercise 2 Compare the corresponding integers for each date If the first date's long integer value is larger than the second date's long integer value, Return true Else Return false b. Include the function written for Exercise 3a in a complete program. Class 11.1 #include <iostream> #include <iomanip> // needed for formatting using namespace std; // declaration section class Date { private: int month; int day; int year; public: Date(int mm = 1, int dd = 1, int yyyy = 2014) // inline constructor {month = mm; day = dd; year = yyyy;} void setDate(int mm, int dd, int yy) // inline mutator {month = mm; day = dd; year = yy;} void showDate(); // accessor bool isLeapYear(); bool operator==(const Date&); // implementation section void Date::showDate() { cout << "The date is " << setfill('0') << setw(2) << month << '/' << setw(2) << day << '/' << setw(2) << year % 100; // extract the last two year digits cout << endl; } bool Date::isLeapYear() { if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)) return true; // is a leap year else return false; // is not a leap year } bool Date::operator==(const Date& date2) { if (day == date2.day && month == date2.month && year == date2.year) return true; else return false; }

          3. (Program) a. Create an operator function for the Date class in Class 11.1 that compares two Date objects and returns a Boolean value of true if the first date is larger than the second; otherwise, it should return a false value. The "larger than" algorithm for this comparison operator function is the following:
Accept one date as the current object being evaluated and a second date as an argument
Determine the later date with the following procedure:
Convert each date to a long integer value in the form yyyymmdd,
using the algorithm in Exercise 2
Compare the corresponding integers for each date
If the first date's long integer value is larger than the second date's
long integer value,
Return true
Else
Return false
b. Include the function written for Exercise 3a in a complete program.

Class 11.1

#include <iostream>
#include <iomanip> // needed for formatting
using namespace std;

// declaration section
class Date
{
private:
int month;
int day;
int year;

public:
Date(int mm = 1, int dd = 1, int yyyy = 2014) // inline constructor
{month = mm; day = dd; year = yyyy;}
void setDate(int mm, int dd, int yy) // inline mutator
{month = mm; day = dd; year = yy;}
void showDate(); // accessor
bool isLeapYear();
bool operator==(const Date&);

// implementation section
void Date::showDate()
{
cout << "The date is " << setfill('0')
<< setw(2) << month << '/'
<< setw(2) << day << '/'
<< setw(2) << year % 100; // extract the last two year digits
cout << endl;
}

bool Date::isLeapYear()
{
if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0))
return true; // is a leap year
else
return false; // is not a leap year
}

bool Date::operator==(const Date& date2)
{
if (day == date2.day && month == date2.month && year == date2.year)
return true;
else
return false;
}

3. (Program) a. Create an operator function for the Date class in Class 11.1 that compares two Date objects and returns a Boolean value of true if the first date is larger than the second; otherwise, it should return a false value. The "larger than" algorithm for this comparison operator function is the following:
Accept one date as the current object being evaluated and a second date as an argument
Determine the later date with the following procedure:
Convert each date to a long integer value in the form yyyymmdd,
using the algorithm in Exercise 2
Compare the corresponding integers for each date
If the first date's long integer value is larger than the second date's
long integer value,
Return true
Else
Return false
b. Include the function written for Exercise 3a in a complete program.

Class 11.1

#include <iostream>
#include <iomanip> // needed for formatting
using namespace std;

// declaration section
class Date

private:
int month;
int day;
int year;

public:
Date(int mm = 1, int dd = 1, int yyyy = 2014) // inline constructor
month = mm; day = dd; year = yyyy;
void setDate(int mm, int dd, int yy) // inline mutator
month = mm; day = dd; year = yy;
void showDate(); // accessor
bool isLeapYear();
bool operator==(const Date );

// implementation section
void Date::showDate()

cout << "The date is " << setfill('0')
<< setw(2) << month << '/'
<< setw(2) << day << '/'
<< setw(2) << year % 100; // extract the last two year digits
cout << endl;

bool Date::isLeapYear()

if ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0))
return true; // is a leap year
else
return false; // is not a leap year

bool Date::operator==(const Date date2)

if (day == date2.day month == date2.month year == date2.year)
return true;
else
return false;

Added by Erika M.

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