4 ·(2t^3 - 1) ·(√(t))^5 = = 4 ·(2t^3 - 1) ·(t^(1)/(2))^5 = 4 ·(2t^3 - 1) ·t^(5)/(2) = 4 ·(2t^3 +

Name: 4 ·(2t^3 - 1) ·(√(t))^5 = = 4 ·(2t^3 - 1) ·(t^(1)/(2))^5 = 4 ·(2t^3 - 1) ·t^(5)/(2) = 4 ·(2t^3 + (5)/(2) - t^(5)/(2)) = 8t^(11)/(2) - 4t^(5)/(2)
Uploaded: 2022-05-09T11:33:34-08:00
Duration: 56 s
Channel: Suman Saurav Thakur
Description: 4 ·(2t^3 - 1) ·(√(t))^5 = = 4 ·(2t^3 - 1) ·(t^(1)/(2))^5 = 4 ·(2t^3 - 1) ·t^(5)/(2) = 4 ·(2t^3 + (5)/(2) - t^(5)/(2)) = 8t^(11)/(2) - 4t^(5)/(2)

1. Start with the given expression: 4('-1}(i}'

Question

4 \cdot (2t^3 - 1) \cdot (\sqrt{t})^5 = \newline = 4 \cdot (2t^3 - 1) \cdot \left(t^{\frac{1}{2}}\right)^5 = 4 \cdot (2t^3 - 1) \cdot t^{\frac{5}{2}} \newline = 4 \cdot (2t^{3 + \frac{5}{2}} - t^{\frac{5}{2}}) \newline = 8t^{\frac{11}{2}} - 4t^{\frac{5}{2}}

          4 \cdot (2t^3 - 1) \cdot (\sqrt{t})^5 = \newline = 4 \cdot (2t^3 - 1) \cdot \left(t^{\frac{1}{2}}\right)^5 = 4 \cdot (2t^3 - 1) \cdot t^{\frac{5}{2}} \newline = 4 \cdot (2t^{3 + \frac{5}{2}} - t^{\frac{5}{2}}) \newline = 8t^{\frac{11}{2}} - 4t^{\frac{5}{2}}